The reaction rate for the reaction [PtCl_4]^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the reaction $[PtCl_4]^{2-} + H_2O \rightleftharpoons [Pt(H_2O)Cl_3]^- + Cl^-$,the rate of the forward reaction is $r_f = k_f [[PtCl_4]^{2-}]$

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) For the reaction $[PtCl_4]^{2-} + H_2O ightleftharpoons [Pt(H_2O)Cl_3]^- + Cl^-$,the rate of the forward reaction is $r_f = k_f [[PtCl_4]^{2-}]$ and the rate of the backward reaction is $r_b = k_b [[Pt(H_2O)Cl_3]^-] [Cl^-]$.At equilibrium,the rate of the forward reaction equals the rate of the backward reaction $(r_f = r_b)$.Therefore,$k_f [[PtCl_4]^{2-}] = k_b [[Pt(H_2O)Cl_3]^-] [Cl^-]$.The equilibrium constant $K_c$ is given by $K_c = \frac{k_f}{k_b} = \frac{[[Pt(H_2O)Cl_3]^-] [Cl^-]}{[[PtCl_4]^{2-}]}$.From the given rate expression,$k_f = 4.8 	imes 10^{-5} \ s^{-1}$ and $k_b = 2.4 	imes 10^{-3} \ M^{-1} s^{-1}$.$K_c = \frac{4.8 	imes 10^{-5}}{2.4 	imes 10^{-3}} = 0.02$.The nearest integer to $0.02$ is $0$.

Similar Questions

Calculate the value of the equilibrium constant $(K_p)$ for the reaction of oxygen gas oxidizing ammonia gas to nitric oxide and water vapor. The pressure of each gas at equilibrium is $0.5 \ atm$. (in $atm$)

For the reaction $PCl_{3(g)} + Cl_{2(g)} \rightleftharpoons PCl_{5(g)}$,the value of $K_p$ at $250 \ ^oC$ is $0.61 \ atm^{-1}$. The value of $K_c$ at this temperature will be .... $(mol \ L^{-1})$.

For the reaction $SO_2 + \frac{1}{2} O_2 \rightleftharpoons SO_3$, if we write $K_p = K_c(RT)^x$, then $x$ becomes

Equilibrium constants $K_1$ and $K_2$ for the following equilibria are given:
$NO_{(g)} + 1/2 O_{2(g)} \rightleftharpoons NO_{2(g)}$
$2NO_{2(g)} \rightleftharpoons 2NO_{(g)} + O_{2(g)}$
What is the relationship between $K_1$ and $K_2$?

For the following gaseous reaction $H_2(g) + I_2(g) \rightleftharpoons 2HI(g)$,the equilibrium constant relationship is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module