The reactivity of 2-bromo-2-methylbutane (I), | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reactivity of alkyl halides towards $S_N2$ reactions is primarily governed by steric hindrance.$S_N2$ reactions involve the nucleophilic attac

Vedclass · Accepted Answer

$II > III > I$

Vedclass · Answer

(C) The reactivity of alkyl halides towards $S_N2$ reactions is primarily governed by steric hindrance.$S_N2$ reactions involve the nucleophilic attack from the back side,which is hindered by the presence of bulky groups around the electrophilic carbon.Therefore,the order of reactivity is $1^{\circ} > 2^{\circ} > 3^{\circ}$.In the given compounds:$1-$bromopentane $(II)$ is a primary $(1^{\circ})$ alkyl halide.$2-$bromopentane $(III)$ is a secondary $(2^{\circ})$ alkyl halide.$2-$bromo$-2-$methylbutane $(I)$ is a tertiary $(3^{\circ})$ alkyl halide.Thus,the correct order of reactivity towards $S_N2$ displacement is $II > III > I$.

The reactivity of $2-$bromo$-2-$methylbutane $(I)$,$1-$bromopentane $(II)$ and $2-$bromopentane $(III)$ towards $S_N2$ displacement is such that :

Similar Questions

Which of the following is not a product of the given reaction?
$1$-chloro-$2$-methylcyclohexane $\xrightarrow{C_2H_5OH/\Delta}$ ?

The product $A$ of the following sequence of reactions is:
Ethylbenzene $\xrightarrow[(b) Cl_2, \Delta]{(a) Br_2, Fe}$ $\xrightarrow{(c) alc. KOH} 'A' \text{ (Major product)}$

In the reaction $2CHCl_3 + O_2 \xrightarrow{X} 2COCl_2 + 2HCl$,$X$ represents:

What is the order of ease of dehydrohalogenation of alkyl halides?

Identify the correct statement for the below given transformation:
$CH_{3}CH_{2}CH_{2}CH(N^{+}(CH_{3})_{3})CH_{3}$ $\xrightarrow{C_{2}H_{5}ONa / C_{2}H_{5}OH} A (\text{major}) + B (\text{minor})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module