The reagent used for the distinction of 1^{ci | vedclass

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Question

(C) The reagent used to distinguish between primary $(1^{\circ})$,secondary $(2^{\circ})$,and tertiary $(3^{\circ})$ amines is benzenesulfonyl chlorid

Vedclass · Accepted Answer

Benzenesulfonyl chloride ($C_6H_5SO_2Cl$,Hinsberg reagent)

Vedclass · Answer

(C) The reagent used to distinguish between primary $(1^{\circ})$,secondary $(2^{\circ})$,and tertiary $(3^{\circ})$ amines is benzenesulfonyl chloride $(C_6H_5SO_2Cl)$,commonly known as the Hinsberg reagent.$1$. Primary $(1^{\circ})$ amines react with benzenesulfonyl chloride to form $N$-alkylbenzenesulfonamide,which is soluble in alkali due to the presence of an acidic hydrogen atom on the nitrogen.$2$. Secondary $(2^{\circ})$ amines react to form $N$,$N$-dialkylbenzenesulfonamide,which is insoluble in alkali because it lacks an acidic hydrogen atom on the nitrogen.$3$. Tertiary $(3^{\circ})$ amines do not react with benzenesulfonyl chloride in the absence of an acidic hydrogen atom on the nitrogen,and thus remain insoluble in the reaction mixture.

The reagent used for the distinction of $1^{\circ}$,$2^{\circ}$ and $3^{\circ}$ amines is

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