The refractive index of the medium is mu = A | vedclass

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(B) The refractive index $\mu$ is a dimensionless quantity,so its dimension is $[M^0 L^0 T^0]$.According to the principle of homogeneity of dimensions

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Area.

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(B) The refractive index $\mu$ is a dimensionless quantity,so its dimension is $[M^0 L^0 T^0]$.According to the principle of homogeneity of dimensions,the dimensions of each term in an equation must be the same.Therefore,the dimensions of $\frac{B}{\lambda^2}$ must be equal to the dimensions of $\mu$ (which is dimensionless).$\left[ \frac{B}{\lambda^2} ight] = [M^0 L^0 T^0]$$[B] = [\lambda^2] 	imes [M^0 L^0 T^0]$Since $\lambda$ is wavelength,its dimension is $[L]$.$[B] = [L^2]$The dimension $[L^2]$ corresponds to the dimension of area.

The refractive index of the medium is $\mu = A + \frac{B}{\lambda^{2}}$,where $A$ and $B$ are constants and $\lambda$ is the wavelength of light. The dimensions of $B$ are the same as that of

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