The Reimer-Tiemann reaction involves the form | vedclass

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Question

(A) The Reimer-Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols. In this reaction,phenol reacts with chloroform $(CHC

Vedclass · Accepted Answer

$X$: Salicylaldehyde,$Y$: o-dichloromethyl phenoxide ion

Vedclass · Answer

(A) The Reimer-Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols. In this reaction,phenol reacts with chloroform $(CHCl_3)$ in the presence of an aqueous base like $KOH$ to form salicylaldehyde $(X)$. The reaction proceeds through the formation of a dichlorocarbene $(:CCl_2)$ intermediate,which attacks the phenoxide ion to form an ortho-dichloromethyl substituted phenoxide intermediate $(Y)$. This intermediate $Y$ then undergoes hydrolysis to yield the final product,salicylaldehyde $(X)$.

The Reimer-Tiemann reaction involves the formation of $X$ from phenol through the intermediate $Y$. What are $X$ and $Y$?

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