The relation between $Z_E, H_E$,and $B_E$ is . . . . . . .

  • A
    $B_E = \sqrt{Z_E^2 + H_E^2}$
  • B
    $B_E = Z_E \cdot H_E$
  • C
    $B_E = \frac{Z_E}{H_E}$
  • D
    $B_E = \frac{H_E}{Z_E}$

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$A$ compass needle oscillates $20$ times per minute at a place where the dip is $30^{\circ}$ and $30$ times per minute where the dip is $60^{\circ}$. The ratio of total magnetic field due to the earth at the two places respectively is $\frac{4}{\sqrt{x}}$. The value of $x$ is $............$.

The correct relation is:
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