The relation between I_p and V_p for a triode | vedclass

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(D) The plate resistance $r_p$ is defined as the reciprocal of the slope of the $I_p - V_p$ characteristic curve at a constant grid potential.Given th

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$8$

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(D) The plate resistance $r_p$ is defined as the reciprocal of the slope of the $I_p - V_p$ characteristic curve at a constant grid potential.Given the relation: $I_p = (0.125V_p - 7.5) 	ext{ mA}$.To find the plate resistance $r_p$,we use the formula: $\frac{1}{r_p} = \frac{\partial I_p}{\partial V_p}$.Differentiating the given equation with respect to $V_p$:$\frac{dI_p}{dV_p} = 0.125 	ext{ mA/V} = 0.125 	imes 10^{-3} 	ext{ A/V}$.Since $\frac{1}{r_p} = 0.125 	imes 10^{-3} 	ext{ S}$,we have:$r_p = \frac{1}{0.125 	imes 10^{-3}} \Omega = \frac{1000}{0.125} \Omega = 8000 \Omega$.Therefore,$r_p = 8 	ext{ k}\Omega$.

The relation between $I_p$ and $V_p$ for a triode is $I_p = (0.125V_p - 7.5) \text{ mA}$. Keeping the grid potential constant at $1 \text{ V}$,the value of $r_p$ will be . . . . . . $\text{k}\Omega$.

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