The relationship between the radius (r) of th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a cubic close packing $(CCP)$ or face-centered cubic $(FCC)$ unit cell,the atoms touch each other along the face diagonal.The length of the fac

Vedclass · Accepted Answer

$r = \frac{a}{2 \sqrt{2}}$

Vedclass · Answer

(B) In a cubic close packing $(CCP)$ or face-centered cubic $(FCC)$ unit cell,the atoms touch each other along the face diagonal.The length of the face diagonal is given by $\sqrt{2} a$,where $a$ is the edge length of the unit cell.Since the face diagonal consists of the radius of the corner atom,the diameter of the face-centered atom,and the radius of the other corner atom,we have: $4r = \sqrt{2} a$.Therefore,the radius $r$ is given by $r = \frac{\sqrt{2} a}{4} = \frac{a}{2 \sqrt{2}}$.

The relationship between the radius $(r)$ of the atom and the edge length $(a)$ of the cubic close packing $(CCP)$ structure is:

Similar Questions

In a close-packed lattice,the number of tetrahedral voids compared to the number of octahedral voids is:

Calculate the volume of $fcc$ unit cell in $cm^3$ if void volume of it is $4.16 \times 10^{-24} \ cm^3$.

What is the minimum number of spheres required to develop a tetrahedral void?

What is the total number of tetrahedral voids in $0.6 \ mole$ of a compound that forms a $hcp$ structure?

Calculate the packing efficiency in a simple cubic metal crystal.

Vedclass Test Series

Exam Paper Generator

Online Exam Module