The resistance of a galvanometer coil is $R$. What is the shunt resistance required to convert it into an ammeter of range $4$ times?

$A$ shunt of resistance $1\,\Omega$ is connected across a galvanometer of $120\,\Omega$ resistance. $A$ total current of $5.5\,A$ is passed through the combination,which gives full-scale deflection in the galvanometer. The current that would give full-scale deflection in the absence of the shunt is nearly ............... $A$.

$A$ student connects a voltmeter,an ammeter,and a resistor as shown in the circuit. If the voltmeter reading is $20 \ V$ and the ammeter reading is $4 \ A$,then the resistance $R$ will be:

The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by $50 \%$. The percentage change in voltage sensitivity of the galvanometer will be $..........\%$

The coil of a moving coil galvanometer has an effective area of $4 \times 10^{-2} \, m^2$. It is suspended in a magnetic field of $5 \times 10^{-2} \, Wb \, m^{-2}$. If the deflection in the galvanometer coil is $0.2 \, rad$, when a current of $5 \, mA$ is passed through it, then

$A$ student is provided with a variable voltage source $V$,a test resistor $R_T=10\,\Omega$,two identical galvanometers $G_1$ and $G_2$,and two additional resistors,$R_1=10\,M\,\Omega$ and $R_2=0.001\,\Omega$. For conducting an experiment to verify Ohm's law,the most suitable circuit is: