The resistance of a conductivity cell containing $0.01 \, M \, KCl$ solution at $298 \, K$ is $1750 \, \Omega$. If the conductivity of $0.01 \, M \, KCl$ solution at $298 \, K$ is $0.152 \times 10^{-3} \, S \, cm^{-1}$,then the cell constant of the conductivity cell is $.......... \, \times 10^{-3} \, cm^{-1}$.

  • A
    $452$
  • B
    $312$
  • C
    $266$
  • D
    $199$

Explore More

Similar Questions

The specific conductivity of a saturated solution of silver chloride is $2 \times 10^{-6} \, S \, cm^{-1}$ at $25 \, ^oC$. What will be the solubility of silver chloride at $25 \, ^oC$ if molar conductivities at infinite dilution of $Ag^{+}$ and $Cl^{-}$ ions are $60$ and $80 \, S \, cm^2 \, mol^{-1}$ respectively?

The resistivity of a $0.8 \ M$ solution of an electrolyte is $5 \times 10^{-3} \ \Omega \ cm$. Its molar conductivity is $..... \times 10^4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. (Nearest integer)

On which of the following factors does electronic conductance $NOT$ depend?

If the conductivity of a $0.5 \ M \ KCl$ solution at $298 \ K$ is $0.024 \ S \ cm^{-1}$,then the molar conductivity of the solution would be $S \ cm^2 \ mol^{-1}$.

What is the conductivity of $0.05 \ M \ BaCl_2$ solution if its molar conductivity is $220 \ \Omega^{-1} \ cm^2 \ mol^{-1}$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo