The resistance of a conducting wire is 10, Om | vedclass

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(A) According to Ohm's Law,the relationship between potential difference $(V)$,current $(I)$,and resistance $(R)$ is given by $V = I 	imes R$.Given:R

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$150$

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(A) According to Ohm's Law,the relationship between potential difference $(V)$,current $(I)$,and resistance $(R)$ is given by $V = I 	imes R$.Given:Resistance $(R)$ = $10\, \Omega$Potential difference $(V)$ = $1.5\, V$To find the current $(I)$,we rearrange the formula: $I = V / R$.Substituting the values: $I = 1.5\, V / 10\, \Omega = 0.15\, A$.To convert the current from Amperes $(A)$ to milliamperes $(mA)$,we multiply by $1000$: $0.15\, A 	imes 1000 = 150\, mA$.Therefore,the electric current flowing through the wire is $150\, mA$.

The resistance of a conducting wire is $10\, \Omega$. If a battery of $1.5\, V$ is connected to it,then how much electric current will flow through it (in $, mA$)?

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