The resistance of a platinum wire at 0^{circ} | vedclass

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(D) The resistance of a conductor at temperature $T$ is given by the formula: $R_T = R_0[1 + \alpha(T - T_0)]$,where $R_T$ is the resistance at temper

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$3 	imes 10^{-2} \,^{\circ}C^{-1}$

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(D) The resistance of a conductor at temperature $T$ is given by the formula: $R_T = R_0[1 + \alpha(T - T_0)]$,where $R_T$ is the resistance at temperature $T$,$R_0$ is the resistance at reference temperature $T_0$,and $\alpha$ is the temperature coefficient of resistance.Given: $R_0 = 2\,\Omega$ at $T_0 = 0^{\circ}C$,and $R_T = 6.8\,\Omega$ at $T = 80^{\circ}C$.Substituting the values into the formula:$6.8 = 2[1 + \alpha(80 - 0)]$$6.8 = 2 + 160\alpha$$4.8 = 160\alpha$$\alpha = \frac{4.8}{160} = \frac{48}{1600} = \frac{3}{100} = 0.03\,^{\circ}C^{-1}$.Thus,$\alpha = 3 	imes 10^{-2}\,^{\circ}C^{-1}$.

The resistance of a platinum wire at $0^{\circ}C$ is $2\,\Omega$ and $6.8\,\Omega$ at $80^{\circ}C$. The temperature coefficient of resistance of the wire is:

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