The resistance of the bulb filament is 100 O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Initial temperature $T_{1} = 100^{\circ} C$,initial resistance $R_{1} = 100 \ \Omega$,final resistance $R_{2} = 200 \ \Omega$,and temperatu

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(A) Given: Initial temperature $T_{1} = 100^{\circ} C$,initial resistance $R_{1} = 100 \ \Omega$,final resistance $R_{2} = 200 \ \Omega$,and temperature coefficient $\alpha = 0.005 \ ^{\circ} C^{-1}$.Using the formula for temperature dependence of resistance: $R_{2} = R_{1}[1 + \alpha(T_{2} - T_{1})]$.Rearranging for $T_{2}$: $T_{2} - T_{1} = \frac{R_{2} - R_{1}}{\alpha R_{1}}$.Substituting the values: $T_{2} - 100 = \frac{200 - 100}{0.005 	imes 100}$.$T_{2} - 100 = \frac{100}{0.5} = 200$.$T_{2} = 200 + 100 = 300^{\circ} C$.

The resistance of the bulb filament is $100 \ \Omega$ at a temperature of $100^{\circ} C$. If its temperature coefficient of resistance is $0.005 \ ^{\circ} C^{-1}$,at what temperature will its resistance become $200 \ \Omega$ (in $^{\circ} C$)?

Similar Questions

$A$ material '$B$' has twice the specific resistance of '$A$'. $A$ circular wire made of '$B$' has twice the diameter of a wire made of '$A$'. Then,for the two wires to have the same resistance,the ratio $\frac{l_B}{l_A}$ of their respective lengths must be

The length of the wire is doubled. Its conductance will be

If a wire is stretched to make it $0.1 \%$ longer,its resistance will.......

Draw the resistivity versus temperature $(\rho \to T)$ graph for metals, alloys, and semiconductors.

$A$ wire of length $1.0\, m$ and diameter $0.6\, cm$ has a resistance of $3.0 \times 10^{-3}\, \Omega$. What will be the resistance between the faces of a disc made of the same material with diameter $2.0\, cm$ and thickness $1.0\, mm$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module