The resistances in the Wheatstone bridge circ | vedclass

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(D) In a balanced Wheatstone bridge,the condition for zero current through the galvanometer is $\frac{R_1}{R_2} = \frac{R_3}{R_4}$ or $\frac{R_1}{R_3}

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The positions of $R_1$ and $R_2$ are interchanged.

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(D) In a balanced Wheatstone bridge,the condition for zero current through the galvanometer is $\frac{R_1}{R_2} = \frac{R_3}{R_4}$ or $\frac{R_1}{R_3} = \frac{R_2}{R_4}$.$1$. If the $EMF$ of the battery is doubled,the ratio of resistances remains unchanged,so the bridge remains balanced.$2$. If the positions of the galvanometer and the battery are interchanged,the condition for balance becomes $\frac{R_1}{R_3} = \frac{R_2}{R_4}$,which is equivalent to the original condition. Thus,the bridge remains balanced.$3$. If all four resistances are doubled,the ratio $\frac{2R_1}{2R_2} = \frac{2R_3}{2R_4}$ still holds,so the bridge remains balanced.$4$. If the positions of $R_1$ and $R_2$ are interchanged,the new condition for zero current would be $\frac{R_2}{R_1} = \frac{R_3}{R_4}$. Since the original condition was $\frac{R_1}{R_2} = \frac{R_3}{R_4}$,this new condition will only hold if $R_1 = R_2$. Since the problem states all resistances are different,the bridge will become unbalanced,and current will flow through the galvanometer.

The resistances in the Wheatstone bridge circuit shown in the diagram are all different,and the current through the galvanometer is zero. If all thermal effects are negligible,the current through the galvanometer will not be zero when:

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