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(C) $1$. The two capacitors of capacitance $C$ at the bottom right are in parallel. Their equivalent capacitance is $C_p = C + C = 2 C$.$2$. This $C_p

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$3 C$

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(C) $1$. The two capacitors of capacitance $C$ at the bottom right are in parallel. Their equivalent capacitance is $C_p = C + C = 2 C$.$2$. This $C_p = 2 C$ is in series with the capacitor of $2 C$ above it. Their equivalent capacitance $C_s$ is given by $\frac{1}{C_s} = \frac{1}{2 C} + \frac{1}{2 C} = \frac{2}{2 C} = \frac{1}{C}$,so $C_s = C$.$3$. This $C_s = C$ is in parallel with the capacitor of $C$ in the middle. Their equivalent capacitance is $C_p' = C + C = 2 C$.$4$. This $C_p' = 2 C$ is in series with the capacitor of $2 C$ above it. Their equivalent capacitance $C_s'$ is given by $\frac{1}{C_s'} = \frac{1}{2 C} + \frac{1}{2 C} = \frac{1}{C}$,so $C_s' = C$.$5$. Finally,this $C_s' = C$ is in parallel with the capacitor of $2 C$ on the left. The total equivalent capacitance is $C_{eq} = C + 2 C = 3 C$.

The resultant capacitance between points $A$ and $B$ in the given circuit is:

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