The resultant gate and its Boolean expression | vedclass

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(A) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate.$1$. The output of the $NOR$ gate with inputs $A$ and $B$ is $C = \overline{A+

Vedclass · Accepted Answer

$OR$,$A+B$

Vedclass · Answer

(A) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate.$1$. The output of the $NOR$ gate with inputs $A$ and $B$ is $C = \overline{A+B}$.$2$. This output $C$ is then passed through a $NOT$ gate.$3$. The final output $Y$ is the complement of $C$,so $Y = \overline{C} = \overline{\overline{A+B}}$.$4$. By the law of double negation,$\overline{\overline{X}} = X$,therefore $Y = A+B$.$5$. $A$ gate with the Boolean expression $Y = A+B$ is an $OR$ gate.

The resultant gate and its Boolean expression for the given circuit is

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