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(D) According to Einstein's photoelectric equation,the maximum kinetic energy of emitted photo-electrons is given by $K_{max} = h
u - \phi_0$,where $

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Increases uniformly with the increase in the frequency of incident light wave

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(D) According to Einstein's photoelectric equation,the maximum kinetic energy of emitted photo-electrons is given by $K_{max} = h
u - \phi_0$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\phi_0$ is the work function.The retarding potential (stopping potential) $V_0$ is related to the maximum kinetic energy by the relation $eV_0 = K_{max}$.Substituting this into the equation,we get $eV_0 = h
u - \phi_0$,which simplifies to $V_0 = \frac{h}{e}
u - \frac{\phi_0}{e}$.Since $h$,$e$,and $\phi_0$ are constants,the stopping potential $V_0$ is a linear function of the frequency $
u$. Therefore,as the frequency of the incident light increases,the retarding potential increases uniformly.

The retarding potential for having zero photo-electron current:

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