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(A) For an inductor,the inductive reactance is $X_L = 2\pi f L$. The current is given by $I = \frac{V}{X_L} = \frac{V}{2\pi f L}$.Thus,$I \propto \fra

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decrease in the first circuit and increase in the other.

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(A) For an inductor,the inductive reactance is $X_L = 2\pi f L$. The current is given by $I = \frac{V}{X_L} = \frac{V}{2\pi f L}$.Thus,$I \propto \frac{1}{f}$. As the frequency $f$ increases,the current $I$ decreases in the first circuit.For a capacitor,the capacitive reactance is $X_C = \frac{1}{2\pi f C}$. The current is given by $I = \frac{V}{X_C} = V(2\pi f C)$.Thus,$I \propto f$. As the frequency $f$ increases,the current $I$ increases in the second circuit.

The same current is flowing in two alternating circuits. The first circuit contains only an inductor and the other contains only a capacitor. If the frequency of the alternating e.m.f. is increased,the values of current will

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