The second ionization energy is maximum for

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Question

(A) The ionization energy increases for atoms or ions that have a stable electronic configuration.The electronic configurations of the unipositive ion

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boron

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(A) The ionization energy increases for atoms or ions that have a stable electronic configuration.The electronic configurations of the unipositive ions are:$B^{+} \rightarrow 1s^2 2s^2$$Be^{+} \rightarrow 1s^2 2s^1$$Mg^{+} \rightarrow [Ne] 3s^1$$Al^{+} \rightarrow [Ne] 3s^2$In $B^{+}$,the electron is to be removed from a completely filled $2s$-subshell,which is highly stable and requires more energy.Thus,the second ionization energy of boron is maximum.

Similar Questions

Assertion $(A)$: The first ionisation energy of $Be$ is greater than that of $B$.
Reason $(R)$: $2p$ orbital has lower energy than $2s$ orbital.

The ionisation energy of nitrogen is more than that of oxygen because :-

The incorrect relation among the following is

Assertion $(A)$: First ionisation enthalpy of oxygen is less than that of nitrogen.
Reason $(R)$: Atoms with half-filled or completely filled orbitals are less stable.
The correct option among the following is:

The successive $5$ ionisation energies of an element are $800, 2427, 3658, 25024$ and $32824 \ kJ/mol$,respectively. By using the above values,predict the group in which the above element is present:

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