The second pregnancy of a woman terminates du | vedclass

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(D) This condition describes $Erythroblastosis 	ext{ } foetalis$, which occurs due to $Rh$ incompatibility.$1$. The mother must be $Rh - ve$ so that

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All the above

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(D) This condition describes $Erythroblastosis 	ext{ } foetalis$, which occurs due to $Rh$ incompatibility.$1$. The mother must be $Rh - ve$ so that her immune system can produce antibodies against $Rh$ antigens.$2$. The father must be $Rh + ve$ for the foetus to inherit the $Rh$ antigen ($Rh + ve$ foetus).$3$. During the first pregnancy, the mother is exposed to the $Rh$ antigens of the $Rh + ve$ foetus, leading to the formation of anti-$Rh$ antibodies in her blood.$4$. In the second pregnancy, these antibodies cross the placenta and destroy the foetal red blood cells, causing severe anaemia. Thus, all the given statements are correct.

The second pregnancy of a woman terminates due to anaemia of the foetus. She has never had a blood transfusion. On the basis of this, which of the following is correct?

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