The sequence of reagents which convert $p-$methyl aniline to $p-$methyl benzoic acid are

  • A
    $KMnO_4 / H^{+} ; NaNO_2 + HCl ; Cu / HCl$
  • B
    $NaNO_2 + HCl / 273 \ K ; Cu / HCl ; KMnO_4 / H^{+}$
  • C
    $NaNO_2 + HCl / 273 \ K ; CuCN / KCN ; H_3O^{+}$
  • D
    $NaNO_2 + HCl / 285 \ K ; KCN ; H_3O^{+}$

Explore More

Similar Questions

Which of the following reacts with chloroform $(CHCl_3)$ and a base $(KOH)$ to form phenyl isocyanide?

The compound which gives an oily nitrosoamine on reaction with nitrous acid at low temperature is:

Which among the following amines has the highest value of $pK_{b}$?

Amines behave as

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: $\alpha$-halocarboxylic acid on reaction with dil. $NH_3$ gives good yield of $\alpha$-amino carboxylic acid whereas the yield of amines is very low when prepared from alkyl halides.
Reason $(R)$: Amino acids exist in zwitter ion form in aqueous medium.
In the light of the above statements,choose the correct answer from the options given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo