The set of quantum numbers for the outermost | vedclass

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(C) The electronic configuration of the $Cu$ $(Z=29)$ atom is $[Ar] 3d^{10} 4s^{1}$.Since the outermost shell is $4s$,the outermost electron resides i

Vedclass · Accepted Answer

$4, 0, 0, +\frac{1}{2}$

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(C) The electronic configuration of the $Cu$ $(Z=29)$ atom is $[Ar] 3d^{10} 4s^{1}$.Since the outermost shell is $4s$,the outermost electron resides in the $4s$ orbital.For the $4s^{1}$ electron:Principal quantum number $(n)$ = $4$.Azimuthal quantum number $(l)$ for $s$-orbital = $0$.Magnetic quantum number $(m_l)$ = $0$.Spin quantum number $(m_s)$ = $+\frac{1}{2}$.Thus,the set of quantum numbers is $(4, 0, 0, +\frac{1}{2})$.

The set of quantum numbers for the outermost electron for copper $(Cu)$ in its ground state is:

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