The sets of molecules in which the central at | vedclass

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(B) To determine the presence of lone pairs on the central atom,we calculate the number of lone pairs using the formula: $	ext{Lone pair} = \frac{1}{

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$ii, iii$ only

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(B) To determine the presence of lone pairs on the central atom,we calculate the number of lone pairs using the formula: $	ext{Lone pair} = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of bonding electrons (monovalent atoms attached).$i$. $SnCl_2$ ($Sn$ has $2$ lone pairs),$NH_3$ ($N$ has $1$ lone pair),$SF_4$ ($S$ has $1$ lone pair).$ii$. $HgCl_2$ ($Hg$ has $0$ lone pairs),$SO_3$ ($S$ has $0$ lone pairs),$SF_6$ ($S$ has $0$ lone pairs).$iii$. $BeCl_2$ ($Be$ has $0$ lone pairs),$BF_3$ ($B$ has $0$ lone pairs),$PCl_5$ ($P$ has $0$ lone pairs).$iv$. $ClF_3$ ($Cl$ has $2$ lone pairs),$BrF_5$ ($Br$ has $1$ lone pair),$XeF_6$ ($Xe$ has $1$ lone pair).Thus,sets $ii$ and $iii$ contain molecules where the central atom has no lone pairs.

The sets of molecules in which the central atom has no lone pair of electrons are:
$i$. $SnCl_2, NH_3, SF_4$
$ii$. $HgCl_2, SO_3, SF_6$
$iii$. $BeCl_2, BF_3, PCl_5$
$iv$. $ClF_3, BrF_5, XeF_6$

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The sets of molecules in which the central atom has no lone pair of electrons are:$i$. $SnCl_2, NH_3, SF_4$$ii$. $HgCl_2, SO_3, SF_6$$iii$. $BeCl_2, BF_3, PCl_5$$iv$. $ClF_3, BrF_5, XeF_6$