The shadow of a tower standing on a level gro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the height of the tower be $h$ and the length of the shadow when the sun's altitude is $45^\circ$ be $x$.In $	riangle PMB$,$	an 45^\circ = \

Vedclass · Accepted Answer

$30(\sqrt{3} + 1) \, m$

Vedclass · Answer

(D) Let the height of the tower be $h$ and the length of the shadow when the sun's altitude is $45^\circ$ be $x$.In $	riangle PMB$,$	an 45^\circ = \frac{h}{x}$ $\Rightarrow 1 = \frac{h}{x}$ $\Rightarrow x = h$.In $	riangle PMA$,$	an 30^\circ = \frac{h}{x + 60} \Rightarrow \frac{1}{\sqrt{3}} = \frac{h}{h + 60}$.$h + 60 = h\sqrt{3} \Rightarrow h(\sqrt{3} - 1) = 60$.$h = \frac{60}{\sqrt{3} - 1} = \frac{60(\sqrt{3} + 1)}{3 - 1} = \frac{60(\sqrt{3} + 1)}{2} = 30(\sqrt{3} + 1) \, m$.

The shadow of a tower standing on a level ground is found to be $60 \, m$ longer when the sun's altitude is $30^\circ$ than when it is $45^\circ$. The height of the tower is

Similar Questions

In $\triangle ABC$,if $\frac{1}{b+c} + \frac{1}{c+a} = \frac{3}{a+b+c}$,then $C$ is equal to (in $^{\circ}$)

If $(1+x+x^2+x^3)^5 = \sum_{k=0}^{15} a_k x^k$,then $\sum_{k=0}^7 a_{2k}$ is equal to

Two animals which are the members of the same order must also be the members of the same

Two bodies of mass $4 ~kg$ and $5 ~kg$ are moving along east and north directions with velocities $5 ~m/s$ and $3 ~m/s$ respectively. The magnitude of the velocity of the centre of mass of the system is

Heat energy is incident on the surface at the rate of $1000 ~J/min$. If the coefficient of absorption is $0.8$ and the coefficient of reflection is $0.1$,then the heat energy transmitted by the surface in $5 ~min$ is: (in $~J$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module