The shape of pentacarbonyl iron,Fe(CO)_5,is: | vedclass

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Question

(B) The central metal atom in $Fe(CO)_5$ is $Fe$. $Fe$ has an atomic number of $26$ and its electronic configuration is $[Ar] 3d^6 4s^2$. In $Fe(CO)_5

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Trigonal bipyramidal

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(B) The central metal atom in $Fe(CO)_5$ is $Fe$. $Fe$ has an atomic number of $26$ and its electronic configuration is $[Ar] 3d^6 4s^2$. In $Fe(CO)_5$,$Fe$ is in the $0$ oxidation state. Due to the strong field ligand $CO$,the electrons in $3d$ and $4s$ orbitals pair up,resulting in $dsp^3$ hybridization. This hybridization corresponds to a trigonal bipyramidal geometry.

The shape of pentacarbonyl iron,$Fe(CO)_5$,is:

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