The shortest distance between the lines $\frac{x - 3}{3} = \frac{y - 8}{-1} = \frac{z - 3}{1}$ and $\frac{x + 3}{-3} = \frac{y + 7}{2} = \frac{z - 6}{4}$ is:

  • A
    $\sqrt{30}$
  • B
    $2\sqrt{30}$
  • C
    $5\sqrt{30}$
  • D
    $3\sqrt{30}$

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