The shortest distance between the skew lines $\vec{r}=(2 \hat{i}-\hat{j})+t(\hat{i}+2 \hat{k})$ and $\vec{r}=(-2 \hat{i}+\hat{k})+s(\hat{i}-\hat{j}-\hat{k})$ is

  • A
    $\frac{3 \sqrt{2}}{\sqrt{7}}$
  • B
    $\frac{3}{\sqrt{7}}$
  • C
    $\frac{3}{\sqrt{14}}$
  • D
    $\frac{4}{\sqrt{14}}$

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