The simplification of 1+frac{1}{2+frac{1}{1-f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To simplify the expression $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$,we solve from the bottom up.First,simplify the denominator of the lowest fracti

Vedclass · Accepted Answer

$\frac{9}{7}$

Vedclass · Answer

(C) To simplify the expression $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$,we solve from the bottom up.First,simplify the denominator of the lowest fraction: $1-\frac{1}{3} = \frac{3-1}{3} = \frac{2}{3}$.Now,the expression becomes $1+\frac{1}{2+\frac{1}{2/3}}$.Next,simplify the term $\frac{1}{2/3}$,which is $\frac{3}{2}$.Now,the expression becomes $1+\frac{1}{2+\frac{3}{2}}$.Simplify the denominator $2+\frac{3}{2} = \frac{4+3}{2} = \frac{7}{2}$.Finally,the expression becomes $1+\frac{1}{7/2} = 1+\frac{2}{7} = \frac{7+2}{7} = \frac{9}{7}$.

The simplification of $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$ yields the result

Similar Questions

The value of $\frac{1}{2} + \frac{1}{2 \cdot 3} + \frac{1}{2 \cdot 3 \cdot 4} + \frac{1}{2 \cdot 3 \cdot 4 \cdot 5}$ is correct to three places of decimal:

If the numerator of a fraction is increased by $2$ and the denominator is increased by $3,$ the fraction becomes $\frac{7}{9},$ and if both the numerator and the denominator are decreased by $1,$ the fraction becomes $\frac{4}{5}.$ What is the original fraction?

If $x+\frac{1}{x}=2,$ then the value of $x^{100}+\frac{1}{x^{100}}$ is

What is the value of $\frac{2.75 \times 2.75 \times 2.75 - 2.25 \times 2.25 \times 2.25}{2.75 \times 2.75 + 2.75 \times 2.25 + 2.25 \times 2.25}$?

If $x=2$,then find the value of $x^{3}+27x^{2}+243x+631$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module