The size of isoelectronic species F^{-}, Ne a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Isoelectronic species have the same number of electrons but different nuclear charges $(Z).$The size of isoelectronic species is primarily determi

Vedclass · Accepted Answer

Nuclear charge $(Z)$

Vedclass · Answer

(A) Isoelectronic species have the same number of electrons but different nuclear charges $(Z).$The size of isoelectronic species is primarily determined by the magnitude of the nuclear charge $(Z).$As the nuclear charge $(Z)$ increases,the force of attraction between the nucleus and the electrons increases,which pulls the electron cloud closer to the nucleus,resulting in a decrease in ionic/atomic size.For the given species:$F^{-} (Z=9), Ne (Z=10), Na^{+} (Z=11)$Since the nuclear charge increases from $F^{-}$ to $Na^{+},$ the size decreases in the order: $F^{-} > Ne > Na^{+}.$Thus,the size is affected by the nuclear charge $(Z).$

The size of isoelectronic species $F^{-},$ $Ne$ and $Na^{+}$ is affected by
$(a)$ Nuclear charge $(Z)$
$(b)$ Valence principal quantum number $(n)$
$(c)$ Electron-electron interaction in the outer orbitals
$(d)$ None of the factors because their size is the same.

Similar Questions

The radius of which ion is closest to that of $Li^{+}$ ion?

Which of the following atoms has the minimum covalent radius?

The atomic radii in the periodic table among elements from right to left:

Which one of the following is expected to have the largest size?

Which one of the following ions has the highest value of ionic radius?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The size of isoelectronic species $F^{-},$ $Ne$ and $Na^{+}$ is affected by$(a)$ Nuclear charge $(Z)$$(b)$ Valence principal quantum number $(n)$$(c)$ Electron-electron interaction in the outer orbitals$(d)$ None of the factors because their size is the same.