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Question

(B) The plate resistance $(r_p)$ of a vacuum diode is defined as the reciprocal of the slope of its plate characteristic curve.Given slope = $2 	imes

Vedclass · Accepted Answer

$50 \, k\Omega$

Vedclass · Answer

(B) The plate resistance $(r_p)$ of a vacuum diode is defined as the reciprocal of the slope of its plate characteristic curve.Given slope = $2 	imes 10^{-2} \, mA/V$.To convert the slope to $A/V$ (or $S$): $2 	imes 10^{-2} 	imes 10^{-3} \, A/V = 2 	imes 10^{-5} \, A/V$.Therefore,$r_p = \frac{1}{	ext{slope}} = \frac{1}{2 	imes 10^{-5}} \, \Omega$.$r_p = 0.5 	imes 10^5 \, \Omega = 50,000 \, \Omega = 50 \, k\Omega$.Thus,the correct option is $B$.

The slope of the plate characteristic of a vacuum diode is $2 \times 10^{-2} \, mA/V$. The plate resistance of the diode will be:

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