The slopes of the lines,making an angle of $45^{\circ}$ with the line $2x - 3y = 5$,are

  • A
    $5, \frac{-1}{5}$
  • B
    $\frac{-1}{5}, -5$
  • C
    $\frac{1}{5}, -5$
  • D
    $5, \frac{1}{5}$

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View Solution

$A$ line passes through the origin and makes equal angles with the positive coordinate axes. It intersects the lines $L_1: 2x + y + 6 = 0$ and $L_2: 4x + 2y - p = 0, p > 0$,at the points $A$ and $B$,respectively. If $AB = \frac{9}{\sqrt{2}}$ and the foot of the perpendicular from the point $A$ on the line $L_2$ is $M$,then $\frac{AM}{BM}$ is equal to

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