The smallest ketone and its next homologue ar | vedclass

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(B) The smallest ketone is acetone $(CH_3COCH_3)$. Its reaction with $NH_2OH$ gives acetone oxime,which is $(CH_3)_2C=NOH$. This molecule has identica

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Three different oximes are formed

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(B) The smallest ketone is acetone $(CH_3COCH_3)$. Its reaction with $NH_2OH$ gives acetone oxime,which is $(CH_3)_2C=NOH$. This molecule has identical groups on the carbon atom,so it does not show geometrical isomerism.The next homologue is butan$-2-$one $(CH_3COCH_2CH_3)$. Its reaction with $NH_2OH$ gives butan$-2-$one oxime,which is $CH_3(C_2H_5)C=NOH$. This molecule has different groups on the carbon atom,so it exhibits geometrical isomerism,resulting in two geometrical isomers ($syn$ and $anti$ forms).Thus,in total,there are $1 + 2 = 3$ different oximes formed.

The smallest ketone and its next homologue are reacted with $NH_2OH$ to form oximes.

Similar Questions

$CH_3-CHO$ $\xrightarrow{HCN} (A)$ $\xrightarrow{H_3O^{+}} (B)$ $\xrightarrow{\Delta} (C)$ $\xrightarrow{LiAlH_4} (D)$ $\xrightarrow{HIO_4} HCHO + (E)$. Compound $(C)$ can show geometrical isomerism. Product $(E)$ of the reaction will be:

Product $(A)$ is

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Which of the following will undergo aldol condensation?

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