The solubility of calcium carbonate $(CaCO_3)$ at $298 \ K$ is $6.4 \times 10^{-5} \ mol \ dm^{-3}$. Calculate the value of solubility product $(K_{sp})$ at the same temperature.

  • A
    $5.06 \times 10^{-10}$
  • B
    $4.096 \times 10^{-9}$
  • C
    $3.05 \times 10^{-10}$
  • D
    $2.8 \times 10^{-9}$

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