The solubility product constants of $Ag_2CrO_4$ and $AgBr$ are $32x$ and $4y$ respectively at $298 \text{ K}$. The value of $(\frac{\text{molarity of } Ag_2CrO_4}{\text{molarity of } AgBr})$ can be expressed as :
- A$\frac{2\sqrt[3]{x}}{y}$
- B$2\sqrt{\frac{x}{y}}$
- C$\sqrt{\frac{x}{y}}$
- D$\frac{\sqrt[3]{x}}{\sqrt{y}}$
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