The solubility product of lead bromide is $8 \times 10^{-5}$. If the salt is $80\%$ dissociated in a saturated solution,find the solubility of the salt.

  • A
    $1.7 \times 10^{-4} \ M$
  • B
    $2.3 \times 10^{-6} \ M$
  • C
    $1.8 \times 10^{-4} \ M$
  • D
    $3.4 \times 10^{-2} \ M$

Explore More

Similar Questions

What is the molar solubility of $Ag_{2}CO_{3}$ $(K_{sp} = 4 \times 10^{-13})$ in $0.1 \ M \ Na_{2}CO_{3}$ solution?

Which of the following is least soluble in water?

The solubility product $(K_{sp})$ of the following compounds are given at $25\,\text{°C}$:
Compound $K_{sp}$
$AgCl$ $1.1 \times 10^{-10}$
$AgI$ $1.0 \times 10^{-16}$
$PbCrO_4$ $4.0 \times 10^{-14}$
$Ag_2CO_3$ $8.0 \times 10^{-12}$

The most soluble and least soluble compounds are respectively:

The concentration of sulphide ion in $0.1 \ M \ HCl$ solution saturated with hydrogen sulphide is $1.0 \times 10^{-19} \ M$. If $10 \ mL$ of this is added to $5 \ mL$ of $0.04 \ M$ solution of the following: $FeSO_4, MnCl_2, ZnCl_2$ and $CdCl_2$,in which of these solutions will precipitation take place? Given $K_{sp}$ for $FeS = 6.3 \times 10^{-18}, MnS = 2.5 \times 10^{-13}, ZnS = 1.6 \times 10^{-24}, CdS = 8.0 \times 10^{-27}$.

If $0.001435 \ g$ of $AgCl$ is present in $100 \ mL$ of water,calculate the $K_{sp}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo