The solubility products of $Al(OH)_3$ and $Zn(OH)_2$ are $8.5 \times 10^{-23}$ and $1.8 \times 10^{-14}$ at room temperature. If the solution contains $Al^{3+}$ and $Zn^{2+}$ ions,the ion first precipitated by adding $NH_4OH$ is
- A$Al^{3+}$
- B$Zn^{2+}$
- Cboth
- Dnone of these
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