The solution of the differential equation $\frac{dy}{dx} = \tan \left(\frac{y}{x}\right) + \frac{y}{x}$ is

  • A
    $\cos \left(\frac{y}{x}\right) = cx$
  • B
    $\sin \left(\frac{y}{x}\right) = cx$
  • C
    $\cos \left(\frac{y}{x}\right) = cy$
  • D
    $\sin \left(\frac{y}{x}\right) = cy$

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Let $y=y(x)$ be the solution of the differential equation $x \tan \left(\frac{y}{x}\right) d y=\left(y \tan \left(\frac{y}{x}\right)-x\right) d x$ for $-1 \leq x \leq 1$,with the initial condition $y\left(\frac{1}{2}\right)=\frac{\pi}{6}$. Then the area of the region bounded by the curves $x=0$,$x=\frac{1}{\sqrt{2}}$,and $y=y(x)$ in the upper half plane is:

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