(A) Given equations are:$(1)$ $x + 2y = 5$$(2)$ $2x + y = 4$From equation $(1)$,we get $x = 5 - 2y$.Substitute this value of $x$ into equation $(2)$:$

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(A) Given equations are:$(1)$ $x + 2y = 5$$(2)$ $2x + y = 4$From equation $(1)$,we get $x = 5 - 2y$.Substitute this value of $x$ into equation $(2)$:$2(5 - 2y) + y = 4$$10 - 4y + y = 4$$10 - 3y = 4$$-3y = 4 - 10$$-3y = -6$$y = 2$Now,substitute $y = 2$ into $x = 5 - 2y$:$x = 5 - 2(2)$$x = 5 - 4$$x = 1$Therefore,the solution is $(x, y) = (1, 2)$.

Class 10 Mathematics Pair of Linear Equations in Two Variables Mix Examples - Pair of Linear Equations in Two Variables

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The solution of the pair of equations $x + 2y = 5$ and $2x + y = 4$ is .........

A
$(1, 2)$
B
$(1, 1)$
C
$(1, -1)$
D
$(2, 2)$

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Mix Examples - Pair of Linear Equations in Two Variables

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The solution of the pair of equations $x + 2y = 5$ and $2x + y = 4$ is .........

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The solution set of the pair of equations $x+y+1=0$ and $3x+3y+k=0$ is an infinite set. Then $k = \dots$

Find the value of $k$ under the given condition for the following pair of linear equations: $2x - 3y = 1$ and $kx + 5y = 7$,such that the system has a unique solution.

The denominator of a fraction is $6$ more than the numerator. If $1$ is added to the numerator and $3$ is subtracted from the denominator,the fraction becomes $\frac{3}{4}$. Find the fraction.

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