The species in which the nitrogen atom is in | vedclass

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Question

(C) The hybridisation of an atom can be determined by calculating the steric number $(SN)$: $SN = \frac{1}{2} [V + M - C + A]$ Where $V$ is the number

Vedclass · Accepted Answer

$NO_2^{+}$

Vedclass · Answer

(C) The hybridisation of an atom can be determined by calculating the steric number $(SN)$: $SN = \frac{1}{2} [V + M - C + A]$ Where $V$ is the number of valence electrons of the central atom, $M$ is the number of monovalent atoms, $C$ is the cationic charge, and $A$ is the anionic charge. For $NO_2^{+}$: $V = 5$ (nitrogen), $M = 0$, $C = 1$, $A = 0$. $SN = \frac{1}{2} [5 + 0 - 1 + 0] = \frac{4}{2} = 2$. $A$ steric number of $2$ corresponds to $sp$ hybridisation. Therefore, the nitrogen atom in $NO_2^{+}$ is $sp$ hybridised.

List-$I$	List-$II$
$(a)$ $SF_6$	$(i)$ $sp^3d^2$
$(b)$ $PCl_5$	(ii) $sp^3d$
$(c)$ $XeF_4$	(iii) $sp^3d^3$
$(d)$ $IF_7$	(iv) $sp^3d^2$

The species in which the nitrogen atom is in a state of $sp$ hybridisation is

Similar Questions

In methane,the bond angle is $......^o$.

Which hybrid orbitals are used by carbon atom in the following molecules?
$(a)$ $CH_3-CH_3$
$(b)$ $CH_3-CH=CH_2$
$(c)$ $CH_3-CH_2-OH$
$(d)$ $CH_3-CHO$
$(e)$ $CH_3COOH$

Match the following:
List-$I$ List-$II$
$(a)$ $SF_6$ $(i)$ $sp^3d^2$
$(b)$ $PCl_5$ (ii) $sp^3d$
$(c)$ $XeF_4$ (iii) $sp^3d^3$
$(d)$ $IF_7$ (iv) $sp^3d^2$

The correct answer is:

What is the bond angle $\angle F-B-F$ in $BF_3$ (in $^{\circ}$)?

The nature of hybridization in $CH_2Cl-CH_2Cl$ for carbon is:

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