The speed of electromagnetic waves in a mediu | vedclass

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(C) The speed of an electromagnetic wave in a medium is given by $v = \frac{c}{\sqrt{\mu_r \epsilon_r}}$,where $c$ is the speed of light in vacuum,$\m

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(C) The speed of an electromagnetic wave in a medium is given by $v = \frac{c}{\sqrt{\mu_r \epsilon_r}}$,where $c$ is the speed of light in vacuum,$\mu_r$ is the relative permeability,and $\epsilon_r$ is the relative permittivity.Given: $v = 1.5 	imes 10^8 \ m/s$,$c = 3 	imes 10^8 \ m/s$,and $\epsilon_r = 2$.Substituting the values: $1.5 	imes 10^8 = \frac{3 	imes 10^8}{\sqrt{\mu_r 	imes 2}}$.Squaring both sides: $(1.5)^2 = \frac{3^2}{2\mu_r} \Rightarrow 2.25 = \frac{9}{2\mu_r}$.Solving for $\mu_r$: $2\mu_r = \frac{9}{2.25} = 4 \Rightarrow \mu_r = 2$.The magnetic susceptibility $\chi_m$ is related to relative permeability by $\mu_r = 1 + \chi_m$.Therefore,$\chi_m = \mu_r - 1 = 2 - 1 = 1$.

The speed of electromagnetic waves in a medium is $1.5 \times 10^8 \ m/s$. If the relative permittivity of that medium is $2$,then its magnetic susceptibility is (speed of light in vacuum is $3 \times 10^8 \ m/s$).

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