The spin magnetic moment of cobalt in the com | vedclass

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(C) In the compound $Hg[Co(SCN)_4]$,the oxidation state of $Co$ is $+2$.$Co^{2+}$ has an electronic configuration of $[Ar] 3d^7$.$SCN^-$ is a weak fie

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$\sqrt{15}$

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(C) In the compound $Hg[Co(SCN)_4]$,the oxidation state of $Co$ is $+2$.$Co^{2+}$ has an electronic configuration of $[Ar] 3d^7$.$SCN^-$ is a weak field ligand,so it forms a tetrahedral complex.In a tetrahedral field,the $d$-orbitals split into $e$ and $t_2$ sets.The configuration for $d^7$ in a tetrahedral field is $e^4 t_2^3$.This results in $n = 3$ unpaired electrons.The spin magnetic moment $\mu_s$ is calculated using the formula $\mu_s = \sqrt{n(n+2)} \ BM$.Substituting $n = 3$: $\mu_s = \sqrt{3(3+2)} = \sqrt{3 	imes 5} = \sqrt{15} \ BM$.

The spin magnetic moment of cobalt in the compound $Hg[Co(SCN)_4]$ is

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