The spin-only magnetic moment value of the mo | vedclass

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Question

(A) The basic character of transition metal oxides decreases as the oxidation state of the metal increases. In $V_2O_3$,the oxidation state of $V$ is

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) The basic character of transition metal oxides decreases as the oxidation state of the metal increases. In $V_2O_3$,the oxidation state of $V$ is $+3$. In $V_2O_4$,the oxidation state of $V$ is $+4$. In $V_2O_5$,the oxidation state of $V$ is $+5$. Thus,$V_2O_3$ is the most basic oxide. The electronic configuration of $V^{3+}$ is $[Ar] 3d^2$. The number of unpaired electrons $(n)$ is $2$. The spin-only magnetic moment is calculated as $\mu = \sqrt{n(n+2)} \ B.M.$. $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ B.M.$. The nearest integer value is $3$.

The spin-only magnetic moment value of the most basic oxide of vanadium among $V_2O_3$,$V_2O_4$,and $V_2O_5$ is $..... \ B.M.$ (Nearest Integer).

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