The stability order of the following resonanc | vedclass

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(A) $(I)$ is a neutral structure with a complete octet for all atoms,making it the most stable resonance structure.Between $(II)$ and $(III)$,structur

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$III < II < I$

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(A) $(I)$ is a neutral structure with a complete octet for all atoms,making it the most stable resonance structure.Between $(II)$ and $(III)$,structure $(II)$ places a negative charge on the more electronegative oxygen atom,whereas structure $(III)$ places a positive charge on the oxygen atom.Since a more electronegative atom is more stable with a negative charge,$(II)$ is more stable than $(III)$.Therefore,the stability order is $III Hence,option $(A)$ is correct.

The stability order of the following resonance structures is:
$I. CH_2=CH-CH=O$
$II. CH_2^+-CH=CH-O^-$
$III. CH_2^--CH=CH-O^+$

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The stability order of the following resonance structures is:$I. CH_2=CH-CH=O$$II. CH_2^+-CH=CH-O^-$$III. CH_2^--CH=CH-O^+$