The standard molar entropy of $H_{2}O_{(l)}$ is $70 \ J \ K^{-1} \ mol^{-1}$. Will the standard molar entropy of $H_{2}O_{(s)}$ be more or less than $70 \ J \ K^{-1} \ mol^{-1}$?

(N/A) The standard molar entropy of $H_{2}O_{(l)}$ is $70 \ J \ K^{-1} \ mol^{-1}$.
The solid form of $H_{2}O$ is ice. In ice,molecules of $H_{2}O$ are held in a rigid crystalline structure,making them less random and disordered than in liquid water.
Entropy is a measure of the randomness or disorder of a system. Since the solid state has a more ordered arrangement of molecules compared to the liquid state,the entropy of the solid is lower.
Therefore,the standard molar entropy of $H_{2}O_{(s)}$ will be less than $70 \ J \ K^{-1} \ mol^{-1}$.