The standard reduction potentials of Zn^{2+}| | vedclass

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(B) Given standard reduction potentials:$E^{\circ}_{Zn^{2+}|Zn} = -0.76 \ V$$E^{\circ}_{Cu^{2+}|Cu} = 0.34 \ V$$E^{\circ}_{Ag^{+}|Ag} = 0.8 \ V$For ce

Vedclass · Accepted Answer

$2 > 1 > 3$

Vedclass · Answer

(B) Given standard reduction potentials:$E^{\circ}_{Zn^{2+}|Zn} = -0.76 \ V$$E^{\circ}_{Cu^{2+}|Cu} = 0.34 \ V$$E^{\circ}_{Ag^{+}|Ag} = 0.8 \ V$For cell $(1)$: $Zn|Zn^{2+}||Cu^{2+}|Cu$$E^{\circ}_{cell(1)} = E^{\circ}_{cathode} - E^{\circ}_{anode} = 0.34 - (-0.76) = 1.10 \ V$For cell $(2)$: $Zn|Zn^{2+}||Ag^{+}|Ag$$E^{\circ}_{cell(2)} = E^{\circ}_{cathode} - E^{\circ}_{anode} = 0.8 - (-0.76) = 1.56 \ V$For cell $(3)$: $Cu|Cu^{2+}||Ag^{+}|Ag$$E^{\circ}_{cell(3)} = E^{\circ}_{cathode} - E^{\circ}_{anode} = 0.8 - 0.34 = 0.46 \ V$Comparing the values: $1.56 \ V (2) > 1.10 \ V (1) > 0.46 \ V (3)$.Therefore,the correct order is $2 > 1 > 3$.

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