(B) According to Einstein's photoelectric equation:$K_{\max} = h\nu - h\nu_0$Since $K_{\max} = eV_0$,where $V_0$ is the stopping potential and $e$ is

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Product of the slope of the line and the charge on the electron

(B) According to Einstein's photoelectric equation:$K_{\max} = h\nu - h\nu_0$Since $K_{\max} = eV_0$,where $V_0$ is the stopping potential and $e$ is the charge of an electron:$eV_0 = h\nu - h\nu_0$Dividing by $e$:$V_0 = (\frac{h}{e})\nu - (\frac{h\nu_0}{e})$Comparing this with the equation of a straight line $y = mx + c$,where $y = V_0$ and $x = \nu$:The slope $m = \frac{h}{e}$.Therefore,Planck's constant $h = m \times e$,which is the product of the slope of the line and the charge on the electron.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

Medium

The stopping potential $V_0$ for photoelectric emission from a metal surface is plotted along the $Y-$ axis and the frequency $\nu$ of incident light along the $X-$ axis. $A$ straight line is obtained as shown. Planck's constant $h$ is given by:

A
Slope of the line
B
Product of the slope of the line and the charge on the electron
C
Product of the intercept along the $Y-$ axis and the mass of the electron
D
Product of the slope and the mass of the electron

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

When light of wavelength $300 \; nm$ falls on a photoelectric emitter,photoelectrons are liberated. For another emitter,light of $600 \; nm$ wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

MediumAIPMT 1993

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The frequency of monochromatic light incident on an emitting surface is $f$. If the threshold frequency for the surface is $f_0$,then the maximum kinetic energy of the emitted photoelectrons is .......

Easy

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In the photoelectric effect,the threshold wavelength of sodium is $5000 \ \mathring A$. Find its work function in $eV$. $(h = 6.6 \times 10^{-34} \ J \cdot s, c = 3 \times 10^8 \ m/s, 1 \ eV = 1.6 \times 10^{-19} \ J)$

Easy

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The work functions of Aluminium and Gold are $4.1\,eV$ and $5.1\,eV$ respectively. The ratio of the slope of the stopping potential versus frequency plot for Gold to that of Aluminium is $.......$

MediumJEE MAIN 2023

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The figure shows the variation of photocurrent with anode potential for four different radiations. Let $f_a$,$f_b$,$f_c$ and $f_d$ be the frequencies for the curves $a$,$b$,$c$ and $d$ respectively.

EasyMHT CET 2024

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The stopping potential $V_0$ for photoelectric emission from a metal surface is plotted along the $Y-$ axis and the frequency $\nu$ of incident light along the $X-$ axis. $A$ straight line is obtained as shown. Planck's constant $h$ is given by:

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When light of wavelength $300 \; nm$ falls on a photoelectric emitter,photoelectrons are liberated. For another emitter,light of $600 \; nm$ wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

The frequency of monochromatic light incident on an emitting surface is $f$. If the threshold frequency for the surface is $f_0$,then the maximum kinetic energy of the emitted photoelectrons is .......

In the photoelectric effect,the threshold wavelength of sodium is $5000 \ \mathring A$. Find its work function in $eV$. $(h = 6.6 \times 10^{-34} \ J \cdot s, c = 3 \times 10^8 \ m/s, 1 \ eV = 1.6 \times 10^{-19} \ J)$

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