The storage battery of a car has an emf of 12 | vedclass

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(C) The $emf$ of the battery is given as $E = 12\; V$.The internal resistance of the battery is $r = 0.4\; \Omega$.To draw the maximum current $(I_{ma

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$30$

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(C) The $emf$ of the battery is given as $E = 12\; V$.The internal resistance of the battery is $r = 0.4\; \Omega$.To draw the maximum current $(I_{max})$ from a battery,the external resistance connected to the circuit must be zero (short circuit condition).According to Ohm's law for a circuit,the current is given by $I = \frac{E}{R + r}$.For maximum current,we set the external resistance $R = 0$.Therefore,$I_{max} = \frac{E}{r} = \frac{12}{0.4}$.$I_{max} = \frac{120}{4} = 30\; A$.Thus,the maximum current that can be drawn from the battery is $30\; A$.

The storage battery of a car has an $emf$ of $12\; V$. If the internal resistance of the battery is $0.4\; \Omega,$ what is the maximum current (in $A$) that can be drawn from the battery?

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