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(A) The molar mass of $H_2O_2$ is $34 \ g/mol$.The molarity $(M)$ of the solution is given by $M = \frac{	ext{mass in } g/L}{	ext{molar mass}} = \fr

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$10$ volume

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(A) The molar mass of $H_2O_2$ is $34 \ g/mol$.The molarity $(M)$ of the solution is given by $M = \frac{	ext{mass in } g/L}{	ext{molar mass}} = \frac{30.36}{34} = 0.893 \ M$.The relation between volume strength and molarity is: $	ext{Volume strength} = 11.2 	imes M$.$	ext{Volume strength} = 11.2 	imes 0.893 \approx 10 	ext{ volumes}$.

The strength in volumes of a solution containing $30.36 \ g/L$ of $H_2O_2$ is

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