The strongest acid is

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(C) The strength of an acid is directly proportional to its $K_a$ value and inversely proportional to its $pK_a$ value. $pK_a = -\log(K_a)$. We conver

Vedclass · Accepted Answer

$HA_3\,\,(pK_a = 2)$

Vedclass · Answer

(C) The strength of an acid is directly proportional to its $K_a$ value and inversely proportional to its $pK_a$ value. $pK_a = -\log(K_a)$. We convert all values to $pK_a$ for comparison: $HA_1: pK_a = 10$. $HA_2: K_a = 10^{-4} \implies pK_a = -\log(10^{-4}) = 4$. $HA_3: pK_a = 2$. $HA_4: K_a = 10^{-7} \implies pK_a = -\log(10^{-7}) = 7$. Comparing the $pK_a$ values: $2 Since the acid with the lowest $pK_a$ is the strongest,$HA_3$ is the strongest acid.

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