The structural formula of a compound is $CH_3 - CH = C = CH_2$. The type of hybridization at the four carbons from left to right are

  • A
    $sp^3, sp^2, sp, sp^2$
  • B
    $sp^2, sp^3, sp^2, sp$
  • C
    $sp^3, sp^2, sp^2, sp^2$
  • D
    $sp^3, sp, sp^2, sp^2$

Explore More

Similar Questions

Which one amongst the following possesses an $sp$ hybridized carbon in its structure?

In the molecule $HC \equiv C - CH_2 - CH = CH - CH_3$,what is the type of hybridization for the $C_2 - C_3$ bond?

Consider a positively charged $C_2H_3$ species in which the positively charged carbon is $sp$-hybridized,the uncharged carbon is $sp^2$-hybridized and an empty $p$-orbital is perpendicular to the $\pi$ system. What is the best description of this cation?

Difficult
View Solution

The compounds containing $sp$-hybridised carbon atom are:
$(I)$ $H_3C-N(CH_3)-CHO$
$(II)$ Pyridine
$(III)$ $H_3C-CN$
$(IV)$ $H_2C=C=CH-CH_3$

Which of the following molecules represents the order of hybridisation $sp^2, sp^2, sp, sp$ from left to right for the carbon atoms?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo